MISCELLANEOUS EXERCISE 4 (II) · Q114
Q.Prove the following by using method of induction: is divisible by , for all .
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Start your 14-day free trial to unlock the full solution →Let . Base: : ; holds. Hypothesis: assume , i.e. . Step: $5^{2k+2}-2^{2k+2}=25\cdot5^{2k}-4\cdot2^{2k}=25(2^{2k}+3m)-4\cdot2^{2k}=25\cdot2^{2k}+75m-4\cdot2^{2k}=21\cdot2^{2k}+75m=3(7\cdot2^{2k}+25m) …
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