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MISCELLANEOUS EXERCISE 4 (I) · Q93

Q.Select the correct answer from the given alternatives. If the coefficient of x2x^2 and x3x^3 in the expansion of (3+ax)9(3+ax)^9 are the same, then the value of aa is: (A) −79-\dfrac{7}{9} (B) −97-\dfrac{9}{7} (C) 79\dfrac{7}{9} (D) 97\dfrac{9}{7}

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Coefficient of x2x^2: 9C237a2=36(2187)a2^9C_23^7a^2=36(2187)a^2. Coefficient of x3x^3: 9C336a3=84(729)a3^9C_33^6a^3=84(729)a^3. Setting equal: 36(2187)a2=84(729)a336(2187)a^2=84(729)a^3; dividing by a2a^2 (as a≠0a\neq0): 36(2187)=84(729)a36(2187)=84(729)a, so a=7873261236=97a=\dfrac{78732}{61236}=\dfrac{9}{7} (simplify using $2 …

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