Skip to content
MISCELLANEOUS EXERCISE 4 (II) · Q118

Q.If the constant term in the expansion of (x3+kx8)11\left(x^3+\dfrac{k}{x^8}\right)^{11} is 13201320, find kk.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
91% · 118/129 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

tr+1=11Cr(x3)11−r(kx8)r=11Crkrx33−11rt_{r+1}={}^{11}C_r(x^3)^{11-r}\left(\dfrac k{x^8}\right)^r={}^{11}C_rk^rx^{33-11r}. Setting 33−11r=033-11r=0 gives r=3r=3. Constant $={}^{11}C_3k^3=165k …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.