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MISCELLANEOUS EXERCISE 4 (II) · Q98

Q.Given that tn+1=5tn−8t_{n+1} = 5t_n - 8, t1=3t_1 = 3, prove by method of induction that tn=5n−1+2t_n = 5^{n-1} +2.

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Let P(n):tn=5n−1+2P(n):t_n=5^{n-1}+2. Base: n=1n=1: 50+2=1+2=3=t15^0+2=1+2=3=t_1; holds. Hypothesis: assume tk=5k−1+2t_k=5^{k-1}+2. Step: tk+1=5tk−8=5(5k−1+2)−8=5k+10−8=5k+2=5(k+1)−1+2t_{k+1}=5t_k-8=5(5^{k-1}+2)-8=5^k+10-8=5^k+2=5^{(k+1)-1}+2, match …

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