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MISCELLANEOUS EXERCISE 4 (II) · Q109

Q.Find the coefficient of x60x^{60} in the expansion of (1x2+x4)18\left(\dfrac{1}{x^2}+x^4\right)^{18}.

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tr+1=18Cr(1x2)18−r(x4)r=18Crx6r−36t_{r+1}={}^{18}C_r\left(\dfrac1{x^2}\right)^{18-r}(x^4)^r={}^{18}C_rx^{6r-36}. Setting 6r−36=606r-36=60 gives r=16r=16. Coefficient $={}^{18}C_{16}= …

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