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MISCELLANEOUS EXERCISE 4 (II) · Q108

Q.Find the coefficient of x6x^6 in the expansion of (3x2−13x)9\left(3x^2-\dfrac{1}{3x}\right)^9.

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tr+1=9Cr(3x2)9−r(−13x)r=9Cr39−2r(−1)rx18−3rt_{r+1}={}^9C_r(3x^2)^{9-r}\left(-\dfrac1{3x}\right)^r={}^9C_r3^{9-2r}(-1)^rx^{18-3r}. Setting 18−3r=618-3r=6 gives r=4r=4. Coefficient $={}^9C_4(-1)^43^{9-8} …

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