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MISCELLANEOUS EXERCISE 4 (II) · Q126

Q.Find the term independent of x in the expansion of (1−x2)(x+2x)6(1 -x^2)\left(x+\dfrac{2}{x}\right)^6.

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General term of (x+2x)6\left(x+\dfrac2x\right)^6: 6Cr2rx6−2r^6C_r2^rx^{6-2r}. From '11': need 6−2r=0⇒r=36-2r=0\Rightarrow r=3, term =6C323=20(8)=160={}^6C_32^3=20(8)=160. From '−x2-x^2': need 6−2r=−2⇒r=46-2r=-2\Rightarrow r=4, term $=-{}^6C_42^4 …

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