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MISCELLANEOUS EXERCISE 4 (II) · Q103

Q.Find tenth term in the expansion of (2x2+1x)12\left(2x^2+\dfrac{1}{x}\right)^{12}.

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Here a=2x2,b=1x,n=12a=2x^2,b=\dfrac1x,n=12. For t10t_{10}, r=9r=9. $t_{10}={}^{12}C_9(2x^2)^3\left(\dfrac1x\right)^9=220(8x^6)x^{-9}=1760x^{- …

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