Skip to content
Answer Questions · Q17

Q.Define coefficient of thermal conductivity. Derive its expression.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
45% · 17/38 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The coefficient of thermal conductivity kk (§7.9.1.2) measures how readily a material conducts heat: a high kk means a good conductor, a low kk means a poor one (an insulator). To derive its expression, consider steady-state conduction through a slab of cross-sectional area AA and thickness xx, with its two faces held at temperatures T1T_1 and T2T_2 (T1>T2T_1>T_2). Experiments show the heat QQ conducted through in time tt is: directly proportional to the area, Q∝AQ\propto A; directly proportional to the temperature difference, Q∝(T1−T2)Q\propto(T_1-T_2); directly proportional to time, Q∝tQ\propto t; and inversely proportional to the thickness, Q∝1/xQ\propto 1/x. Combining these four proportionalities with a single constant of proportionality kk gives Q=kA(T1−T2)txQ = \dfrac{kA(T_1-T_2)t}{x} (Eq. 7.34), and rearranging, k=QxA(T1−T2)tk = \dfrac{Qx}{A(T_1-T_2)t} (Eq. 7.35). Setting A=1 m2A=1\text{ m}^2, $(T_1-T_2)=1 …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.