Q.Define coefficient of thermal conductivity. Derive its expression.
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Start your 14-day free trial to unlock the full solution →The coefficient of thermal conductivity (§7.9.1.2) measures how readily a material conducts heat: a high means a good conductor, a low means a poor one (an insulator). To derive its expression, consider steady-state conduction through a slab of cross-sectional area and thickness , with its two faces held at temperatures and (). Experiments show the heat conducted through in time is: directly proportional to the area, ; directly proportional to the temperature difference, ; directly proportional to time, ; and inversely proportional to the thickness, . Combining these four proportionalities with a single constant of proportionality gives (Eq. 7.34), and rearranging, (Eq. 7.35). Setting , $(T_1-T_2)=1 …
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