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Numericals · Q35

Q.The rate of flow of heat through a copper rod with temperature difference 30 °C is 1500 cal/s. Find the thermal resistance of the copper rod.

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Given rate of heat flow Pcond=1500 cal/sP_{cond} = 1500\text{ cal/s} and temperature difference ΔT=30 °C\Delta T = 30\,°\text{C}. Using RT=T1−T2PcondR_T = \dfrac{T_1-T_2}{P_{cond}} (§7.9.1.3): $R_T = \dfrac …

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