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Numericals · Q36

Q.An electric kettle takes 20 minutes to heat a certain quantity of water from 0°C to its boiling point. It requires 90 minutes to turn all the water at 100°C into steam. Find the latent heat of vaporisation. (Specific heat of water = 1 cal/g°C)

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Assume the kettle delivers heat at a constant rate (power) throughout. Heat needed to raise mass mm (grams) of water from 0°C to 100°C: Q1=m×1 cal/g°C×100=100m calQ_1 = m\times1\text{ cal/g°C}\times100 = 100m\text{ cal}, delivered in 20 minutes, so the heating rate is 100m20=5m cal/min\dfrac{100m}{20}=5m\text{ cal/min}. At this SAME rate, the heat delivered over the next 90 minutes (converting all the water t …

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