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Long Answer Questions · Q3

Q.Describe the process of translation in protein synthesis.

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Translation converts the codon sequence of mRNA into a polypeptide, in three stages -- initiation, elongation and termination -- using tRNAs to deliver amino acids at the ribosome.

Step 1. Initiation: The small ribosomal subunit binds the mRNA near its 5' end; the initiator tRNA, carrying methionine (or formyl-methionine in prokaryotes), base-pairs its anticodon (UAC) with the initiation codon AUG. The large subunit then joins (requiring Mg2+ ions), positioning the initiator tRNA in the ribosome's P site while the A site remains vacant.

Step 2. Elongation -- codon recognition: A charged aminoacyl-tRNA carrying the next amino acid enters the vacant A site, its anticodon pairing with the exposed mRNA codon.

Step 3. Elongation -- peptide bond formation: The amino acid on the P-site tRNA is joined to the amino acid on the A-site tRNA by a peptide bond, a reaction catalysed by the ribosome's own ribozyme (peptidyl transferase) activity; the now-uncharged tRNA is released from the P site.

Step 4. Elongation -- translocation: The ribosome moves one codon along the mRNA, shifting the peptidyl-tRNA from the A site to the P site and ejecting the previous, discharged tRNA via the E site, so a new A site is exposed for the next incoming tRNA; this three-step cycle repeats, adding one amino acid roughly every 0.1 second.

Step 5. Termination: When a stop codon (UAA, UAG or UGA) enters the A site, no tRNA recognises it; instead a release factor binds the stop codon, the completed polypeptide is released into the cytoplasm, and the two ribosomal subunits dissociate along with the last tRNA and the mRNA.

✓Final answer

Translation proceeds through initiation (small subunit + initiator tRNA at AUG, then large subunit joining), repeated elongation cycles (codon recognition, peptide-bond formation, translocation), and termination (release-factor-mediated release of the polypeptide at a stop codon).

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