Q.$CH_3-CH=CH_2 \xrightarrow{HI/peroxide}$ ? The major product of the above reaction is,
a. $I-CH_2-CH=CH_2$
b. $CH_3-CH_2-CH_2I$
c. $CH_3-\underset{I}{\underset{|}{CH}}-CH_3$
d. $CH_3-\underset{I}{\underset{|}{CH}}-\underset{OH}{\underset{|}{CH_2}}$

Thionyl chloride has the formula SOCl2 and is the preferred reagent for converting alcohols into alkyl chlorides.

SOCl2 (thionyl chloride) reacts with an alcohol to give the corresponding chloroalkane, with sulphur dioxide and hydrogen chloride as the only by-products, both of which escape as gases:

R-OH + SOCl2 --(pyridine)--> R-Cl + SO2(g) + HCl(g)

Because the by-products are gaseous and leave the reaction mixture, this method (Darzen's process) gives a relatively pure product and is preferred over using HCl/ZnCl2 or PCl5 for this conversion.

SOCl$_2$ replaces the –OH of cyclohexanol by –Cl, giving chlorocyclohexane; SO$_2$ and HCl are the by-products.

Cyclohexanol reacts with thionyl chloride (best carried out in the presence of pyridine, which absorbs the HCl formed) by the following overall equation:

$C_6H_{11}OH + SOCl_2 \xrightarrow{\text{pyridine}} C_6H_{11}Cl + SO_2\uparrow + HCl\uparrow$

Mechanism (briefly): the oxygen of the alcohol attacks the electrophilic sulfur of SOCl$_2$, displacing Cl$^-$ and forming an alkyl chlorosulfite ester, $C_6H_{11}-O-S(=O)-Cl$, with loss of HCl. This chlorosulfite is a good leaving group; the chloride ion (released in the same step, or delivered by pyridinium chloride) then displaces it, either from the front side (SN$i$, retention of configuration, in the absence of a base) or the back side (SN2, inversion, when pyridine is present to remove HCl and free Cl$^-$), giving the monochloro product with loss of SO$_2$.

This reaction is the preferred laboratory method of preparing an alkyl chloride from an alcohol because both by-products (SO$_2$, HCl) are gases that escape the reaction mixture, giving a clean product without side reactions typical of HCl/ZnCl$_2$ or PCl$_5$ routes.

Thionyl chloride converts an alcohol directly into the corresponding chloroalkane, with both by-products escaping as gases.

The missing reagent is thionyl chloride, SOCl2. This reaction (called Darzens' process) converts an alcohol into the corresponding chloroalkane:

R-OH + SOCl2 → R-Cl + SO2↑ + HCl↑

This method is preferred over using HCl directly because both by-products (SO2 and HCl) are GASES that simply escape the reaction mixture, leaving a purer haloalkane product without the need for extensive purification (unlike, say, reaction with HX which can leave the product contaminated with water/acid).

Butan-1-ol is converted to 1-bromobutane using PBr3 (3 CH3CH2CH2CH2OH + PBr3 → 3 CH3CH2CH2CH2Br + H3PO3).

Alcohols are converted to alkyl bromides by phosphorus tribromide (PBr3), a standard reagent that replaces the -OH group by -Br:

3 R-OH + PBr3 → 3 R-Br + H3PO3

So for butan-1-ol:

3 CH3CH2CH2CH2OH + PBr3 → 3 CH3CH2CH2CH2Br + H3PO3

• Br2 alone does not convert an alcohol to an alkyl bromide.
• CHBr3 (bromoform) and CH3Br are not reagents for this substitution.

PBr3 (like the phosphorus halides and also HBr/red P) cleanly gives the primary alkyl bromide.

Replacing Cl/Br by F using a metal fluoride is named the Swarts reaction.

In the Swarts reaction, an alkyl chloride or bromide is heated with a metallic fluoride such as $AgF$, $Hg_2F_2$, $CoF_2$ or $SbF_3$; the halogen is exchanged for fluorine because the M–F bond formed is thermodynamically very stable:

$CH_3Cl + AgF \rightarrow CH_3F + AgCl\downarrow$

Finkelstein reaction (part a) is the analogous exchange of Cl/Br for I using NaI/acetone; Williamson's synthesis makes ethers; Wurtz reaction couples two alkyl halides with Na to give a higher alkane — none of these produce an alkyl fluoride.

Thionyl chloride converts alcohols into alkyl chlorides while producing only gaseous by-products, so the product needs no further purification — this is why it (the Darzens procedure) is the preferred laboratory method.

The reaction of an alcohol with thionyl chloride proceeds as:

$R{-}OH + SOCl_2 \xrightarrow{\text{pyridine}} R{-}Cl + SO_2\uparrow + HCl\uparrow$

Both by-products, sulphur dioxide ($SO_2$) and hydrogen chloride ($HCl$), are gases at room temperature, so they escape from the reaction mixture spontaneously, leaving behind only the desired alkyl chloride (with no other solid or liquid contaminant to remove).

This is in contrast to alternative methods:

• $R{-}OH + PCl_5 \to R{-}Cl + POCl_3 + HCl$ — the by-product $POCl_3$ (phosphorus oxychloride) is a liquid that must be separated from the product by distillation.
• $3R{-}OH + PCl_3 \to 3R{-}Cl + H_3PO_3$ — the by-product $H_3PO_3$ (phosphorous acid) is also non-volatile and must be removed.

Since the $SOCl_2$ method gives a clean product directly (no distillation/separation required, this method is called the Darzens procedure), it is the preferred laboratory route for converting alcohols to alkyl chlorides.

Alkyl chloride + metallic fluoride $\rightarrow$ alkyl fluoride is the Swarts reaction.

The Swarts reaction is the method by which an alkyl fluoride is prepared by heating an alkyl chloride (or bromide) with a metallic fluoride such as $AgF$, $Hg_2F_2$, $CoF_2$, or $SbF_3$; the halogen exchange occurs because these fluorides provide fluoride ion that displaces the heavier halide.

$R\text{-}Cl + AgF \rightarrow R\text{-}F + AgCl$