Q.Propene to propan-1-ol
Concept understanding — Preparation and Reactions of Haloalkanes
Preparation and Reactions of Haloalkanes
Preparation of alkyl halides is by: addition of HX to alkenes (Markovnikov); treating alcohols with HX, with PCl3/PCl5, with SOCl2, or with Lucas reagent (ZnCl2/HCl); and free-radical halogenation of alkanes in sunlight. (Direct free-radical chlorination of an alkane is unselective, so it is not the preferred route to a single pure alkyl chloride.) When PCl3 reacts with ethanol the inorganic product is phosphorous acid H3PO3.
Reactions: alkyl halides are reduced to alkanes by nascent hydrogen or a Zn–Cu couple in alcohol (CH3CH2Br+2[H]→CH3CH3+HBr). Chloroform is slowly oxidised in air/light to poisonous phosgene (COCl2), so it is stored in dark bottles. Alkyl halides also undergo SN1/SN2 substitution and elimination.
Preparation routes for alkyl halides sit at the heart of the NCERT/CBSE Class 12 Chemistry "Haloalkanes and Haloarenes" chapter and are a staple of "haloalkanes preparation and reactions class 12 chemistry" revision searches. These reactions are also frequently tested as JEE Main and NEET organic-chemistry numericals and reasoning questions.
Anti-Markovnikov HBr addition (peroxide) puts Br on the terminal carbon, then hydrolysis with aqueous KOH swaps it for -OH.
Propene --HBr, peroxide--> 1-bromopropane --aq. KOH, heat--> propan-1-ol.
Step 1. Get the halogen onto the terminal (C-1) carbon. Ordinary (Markovnikov) addition of HBr to propene would put Br on C-2, giving 2-bromopropane, which would only ever give propan-2-ol -- the wrong regiochemistry. Using HBr in the presence of peroxide instead reverses the regiochemistry (anti-Markovnikov, the peroxide effect, section 10.3.2/Class 11 15.2.4), so Br adds to the terminal carbon: CH3-CH=CH2 + HBr (peroxide) -> CH3-CH2-CH2-Br (1-bromopropane).
Step 2. Hydrolyse the halide to the alcohol. 1-Bromopropane treated with aqueous NaOH/KOH under heat undergoes nucleophilic substitution (Table 10.3, entry 1), replacing Br with OH: CH3-CH2-CH2-Br + aq. KOH (heat) -> CH3-CH2-CH2-OH (propan-1-ol) + KBr.
Propene --HBr, peroxide--> 1-bromopropane --aq. KOH, heat--> propan-1-ol.
Using the peroxide effect to get the halogen onto the correct (terminal) carbon first, then a standard hydroxide substitution.
- Forgetting the peroxide and using ordinary HBr addition -- that installs the halogen on the WRONG carbon (C-2), which can never be hydrolysed to propan-1-ol, only to propan-2-ol.
- CBSE 2025Set ANNUAL1 markMCQQ.Thionyl chloride is -(a) SOCl2(b) SO2Cl2(c) COCl2(d) SOCl3
›Reveal solutionSolution
Thionyl chloride has the formula SOCl2 and is the preferred reagent for converting alcohols into alkyl chlorides.
SOCl2 (thionyl chloride) reacts with an alcohol to give the corresponding chloroalkane, with sulphur dioxide and hydrogen chloride as the only by-products, both of which escape as gases:
R-OH + SOCl2 --(pyridine)--> R-Cl + SO2(g) + HCl(g)
Because the by-products are gaseous and leave the reaction mixture, this method (Darzen's process) gives a relatively pure product and is preferred over using HCl/ZnCl2 or PCl5 for this conversion.
✓Final answer(a) SOCl2.
- CBSE 2025Set ANNUAL1 markQ.Draw the structure of the major monohalo product: cyclohexanol (cyclohexane ring with an −OH substituent) +SOCl2→?
›Reveal solutionSolution
SOCl2 replaces the –OH of cyclohexanol by –Cl, giving chlorocyclohexane; SO2 and HCl are the by-products.
Cyclohexanol reacts with thionyl chloride (best carried out in the presence of pyridine, which absorbs the HCl formed) by the following overall equation:
C6H11OH+SOCl2pyridineC6H11Cl+SO2↑+HCl↑
Mechanism (briefly): the oxygen of the alcohol attacks the electrophilic sulfur of SOCl2, displacing Cl− and forming an alkyl chlorosulfite ester, C6H11−O−S(=O)−Cl, with loss of HCl. This chlorosulfite is a good leaving group; the chloride ion (released in the same step, or delivered by pyridinium chloride) then displaces it, either from the front side (SNi, retention of configuration, in the absence of a base) or the back side (SN2, inversion, when pyridine is present to remove HCl and free Cl−), giving the monochloro product with loss of SO2.
This reaction is the preferred laboratory method of preparing an alkyl chloride from an alcohol because both by-products (SO2, HCl) are gases that escape the reaction mixture, giving a clean product without side reactions typical of HCl/ZnCl2 or PCl5 routes.
✓Final answerChlorocyclohexane, C6H11Cl — the cyclohexane ring with the –OH replaced by –Cl.
- CBSE 2024Set ANNUAL1 markQ.Complete the reaction: R-OH + ? → R-Cl + SO2 + HCl.
›Reveal solutionSolution
Thionyl chloride converts an alcohol directly into the corresponding chloroalkane, with both by-products escaping as gases.
The missing reagent is thionyl chloride, SOCl2. This reaction (called Darzens' process) converts an alcohol into the corresponding chloroalkane:
R-OH + SOCl2 → R-Cl + SO2↑ + HCl↑
This method is preferred over using HCl directly because both by-products (SO2 and HCl) are GASES that simply escape the reaction mixture, leaving a purer haloalkane product without the need for extensive purification (unlike, say, reaction with HX which can leave the product contaminated with water/acid).
✓Final answerThe missing reagent is thionyl chloride (SOCl2): R-OH + SOCl2 → R-Cl + SO2 + HCl.
- CBSE 2022Set E1 markMCQQ.The reagent which is used to prepare 1-Bromobutane from Butan-1-ol is(a) CHBr3(b) Br2(c) CH3Br(d) PBr3
›Reveal solutionSolution
Butan-1-ol is converted to 1-bromobutane using PBr3 (3 CH3CH2CH2CH2OH + PBr3 → 3 CH3CH2CH2CH2Br + H3PO3).
Alcohols are converted to alkyl bromides by phosphorus tribromide (PBr3), a standard reagent that replaces the -OH group by -Br:
3 R-OH + PBr3 → 3 R-Br + H3PO3
So for butan-1-ol:
3 CH3CH2CH2CH2OH + PBr3 → 3 CH3CH2CH2CH2Br + H3PO3
- Br2 alone does not convert an alcohol to an alkyl bromide.
- CHBr3 (bromoform) and CH3Br are not reagents for this substitution.
PBr3 (like the phosphorus halides and also HBr/red P) cleanly gives the primary alkyl bromide.
✓Final answer(D) PBr3.
- CBSE 2020Set ANNUAL1 markMCQQ.Conversion of methyl chloride into methyl fluoride is known as _______.(a) Finkelstein reaction(b) Swarts reaction(c) Williamson's synthesis(d) Wurtz reaction
›Reveal solutionSolution
Replacing Cl/Br by F using a metal fluoride is named the Swarts reaction.
In the Swarts reaction, an alkyl chloride or bromide is heated with a metallic fluoride such as AgF, Hg2F2, CoF2 or SbF3; the halogen is exchanged for fluorine because the M–F bond formed is thermodynamically very stable:
CH3Cl+AgF→CH3F+AgCl↓
Finkelstein reaction (part a) is the analogous exchange of Cl/Br for I using NaI/acetone; Williamson's synthesis makes ethers; Wurtz reaction couples two alkyl halides with Na to give a higher alkane — none of these produce an alkyl fluoride.
✓Final answer(b) Swarts reaction
- CBSE 2018Set ANNUAL1 markQ.Explain why thionyl chloride (SOCl2) method is preferred for preparing alkyl chlorides from alcohols.
›Reveal solutionSolution
Thionyl chloride converts alcohols into alkyl chlorides while producing only gaseous by-products, so the product needs no further purification — this is why it (the Darzens procedure) is the preferred laboratory method.
The reaction of an alcohol with thionyl chloride proceeds as:
R−OH+SOCl2pyridineR−Cl+SO2↑+HCl↑
Both by-products, sulphur dioxide (SO2) and hydrogen chloride (HCl), are gases at room temperature, so they escape from the reaction mixture spontaneously, leaving behind only the desired alkyl chloride (with no other solid or liquid contaminant to remove).
This is in contrast to alternative methods:
- R−OH+PCl5→R−Cl+POCl3+HCl — the by-product POCl3 (phosphorus oxychloride) is a liquid that must be separated from the product by distillation.
- 3R−OH+PCl3→3R−Cl+H3PO3 — the by-product H3PO3 (phosphorous acid) is also non-volatile and must be removed.
Since the SOCl2 method gives a clean product directly (no distillation/separation required, this method is called the Darzens procedure), it is the preferred laboratory route for converting alcohols to alkyl chlorides.
✓Final answerBecause both by-products of the SOCl2 reaction (SO2 and HCl) are gases that escape on their own, giving pure alkyl chloride without any extra purification step.
- CBSE 2016Set ANNUAL1 markMCQQ.The preparation of alkyl fluoride from alkyl chloride, in presence of metallic fluorides is known as _______.(a) Williamson's reaction(b) Finkelstein reaction(c) Swarts reaction(d) Wurtz reaction
›Reveal solutionSolution
Alkyl chloride + metallic fluoride → alkyl fluoride is the Swarts reaction.
The Swarts reaction is the method by which an alkyl fluoride is prepared by heating an alkyl chloride (or bromide) with a metallic fluoride such as AgF, Hg2F2, CoF2, or SbF3; the halogen exchange occurs because these fluorides provide fluoride ion that displaces the heavier halide.
R-Cl+AgF→R-F+AgCl
✓Final answer(c) Swarts reaction.
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