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Do as directed · Q3

Q.Identify chiral molecule/s from the following.
a. CH3−CH∣OH−CH2−CH3CH_3-\underset{OH}{\underset{|}{CH}}-CH_2-CH_3
b. CH3−CH2−CH∣Br−CH2−CH3CH_3-CH_2-\underset{Br}{\underset{|}{CH}}-CH_2-CH_3
c. CH3−CH2−CH2−CH2BrCH_3-CH_2-CH_2-CH_2Br
d. CH3−CH∣CH3−CH3−CH3CH_3-\underset{CH_3}{\underset{|}{CH}}-CH_3-CH_3 (Option d is carried exactly as the book prints it — "CH₃-CH-CH₃-CH₃" with a CH₃ drop-bond — a malformed formula in the original paper.)

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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✓ Free question

Test each carbon for four DIFFERENT groups:

  • a. CH₃-CH(OH)-CH₂-CH₃ (butan-2-ol) — C-2 bears H, OH, CH₃, C₂H₅: four different groups → chiral ✓
  • b. CH₃-CH₂-CH(Br)-CH₂-CH₃ (3-bromopentane) — C-3 bears H, Br and TWO identical ethyl groups → achiral ✗
  • c. CH₃-CH₂-CH₂-CH₂Br (1-bromobutane) — primary, no stereocentre ✗
  • d. as printed (the malformed 2-methyl formula) — every candidate carbon carries two identical CH₃ groups → achiral ✗
✓Final answer

Only a (butan-2-ol) is chiral

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