Q.From the cis-polyisoprene structure of natural rubber explain the low strength of van der Waals forces in it.
Explain how vulcanization of natural rubber improves its elasticity ? (Hint : consider the intermolecular links.)
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Step 1. In cis-polyisoprene, the cis geometry at each retained double bond puts a kink/bend in the chain at every repeat unit, so the overall chain cannot lie flat or pack tightly against its neighbours -- it coils loosely instead.
Step 2. Because the chains are kept apart by this coiled, irregular shape, the only forces acting between neighbouring chains are weak, short-range van der Waals forces -- there is comparatively little chain-to-chain contact area for these forces to act over, so their net strength is low.
Step 3. This weak, loose packing is exactly what lets natural rubber stretch easily under an applied force -- but without any crosslinks, the chains can also permanently slide past one another, so unvulcanized rubber does not fully recover its shape and stays soft/tacky. …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.