Q.What is the oxidation state of Manganese in
Step 1. Set up the oxidation-state equation for MnO4 2-. Let Mn's oxidation state be x. Oxygen is essentially always -2 in oxyanions, and there are 4 oxygens, contributing 4x(-2) = -8. The whole ion carries a -2 charge, so x + (-8) = -2, giving x = +6.
Step 2. Set up the same equation for MnO4-. Again 4 oxygens contribute -8, but this ion carries a -1 charge overall, so x + (-8) = -1, giving x = +7.
Step 3. Cross-check against the chapter's own chemistry. MnO4 2- is the green potassium manganate intermediate of Section 8.7.1 (Mn +6), which disproportionates into MnO4- (permanganate, Mn +7, the final product) and MnO2 (Mn +4) -- consistent with +6 sitting between the +7 and +4 species it disproportionates into.
(i) +6 in MnO4 2- (manganate) (ii) +7 in MnO4- (permanganate)
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