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Miscellaneous 7 (I) · Q46
Q.

The expected value of X for the following p.m.f.

X–2–1012
P (X)0.30.30.10.050.25

(A) 0.85

(B) – 0.35

(C) 0.15

(D) – 0.15

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$E(X)=(-2)(0.3)+(-1)(0.3)+0(0.1)+1(0.05)+2(0.25)=-0.6-0.3+0+0.05+0.5=- …

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