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Miscellaneous 7 (II) · Q64

Q.A player tosses two coins he wins 10 if 2 heads appears , 5 if 1 head appears and ` 2 if no head appears. Find the expected winning amount and variance of winning amount.

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With 2 coins, P(2 heads)=1/4P(2\ heads)=1/4 (win ₹10), P(1 head)=1/2P(1\ head)=1/2 (win ₹5), P(0 heads)=1/4P(0\ heads)=1/4 (win ₹2). E(X)=10(1/4)+5(1/2)+2(1/4)=2.5+2.5+0.5=5.5E(X)=10(1/4)+5(1/2)+2(1/4)=2.5+2.5+0.5=5.5. E(X2)=100(1/4)+25(1/2)+4(1/4)=25+12.5+1=38.5E(X^2)=100(1/4)+25(1/2)+4(1/4)=25+12.5+1=38.5. $Va …

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