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Miscellaneous 7 (II) · Q58
Q.

A random variable X has the following probability distribution.

X01234567
P (X)0k2k2k3kk²2k²7k² + k

Determine (i) k (ii) P (X > 6) (iii) P (0 < X < 3)

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10k2+9k−1=0⇒k=0.110k^2+9k-1=0\Rightarrow k=0.1 (rejecting the negative root).

(ii) P(X>6)=P(X=7)=7k2+k=0.07+0.1=0.17P(X>6)=P(X=7)=7k^2+k=0.07+0.1=0.17. …

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