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Miscellaneous 7 (II) · Q54

Q.The p.m.f. of a r.v. X is given by P (X = x) = (5 Cx)/2⁵, for x = 0, 1, 2, 3, 4, 5 and = 0, otherwise. Then show that P (X ≤ 2) = P (X ≥ 3).

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P(X≤2)=(50)+(51)+(52)32=1+5+1032=12P(X\le2)=\dfrac{\binom50+\binom51+\binom52}{32}=\dfrac{1+5+10}{32}=\dfrac12. P(X≥3)=(53)+(54)+(55)32=10+5+132=12P(X\ge3)=\dfrac{\binom53+\binom54+\binom55}{32}=\dfrac{10+5+1}{32}=\dfrac12. Both equal 1/21/2, so they are equal — this also follows immediately from $\b …

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