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Miscellaneous 7 (II) · Q59
Q.

The following is the c.d.f. of r.v. X

X–3–2–101234
F (X)0.10.30.50.650.750.850.91

Find p.m.f. of X.

  1. P (–1 ≤ X ≤ 2)
  2. P (X ≤ 3/ X > 0)
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Since F jumps by p(x) at each possible value: p(−3)=0.1p(-3)=0.1; p(−2)=0.2p(-2)=0.2; p(−1)=0.2p(-1)=0.2; p(0)=0.15p(0)=0.15; p(1)=0.1p(1)=0.1; p(2)=0.1p(2)=0.1; p(3)=0.05p(3)=0.05; p(4)=0.1p(4)=0.1 (sum = 1).

(i) P(−1≤X≤2)=F(2)−F(−2)=0.85−0.3=0.55P(-1\le X\le2)=F(2)-F(-2)=0.85-0.3=0.55. …

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