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Miscellaneous 7 (II) · Q53
Q.

The following probability distribution of r.v. X

X = x–3–2–10123
P (X = x)0.050.10.150.200.250.150.1

Find the probability that

  1. X is positive.
  2. X is non negative.
  3. X is odd.
  4. X is even.
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The table gives P(−3)=0.05,P(−2)=0.1,P(−1)=0.15,P(0)=0.20,P(1)=0.25,P(2)=0.15,P(3)=0.1P(-3)=0.05, P(-2)=0.1, P(-1)=0.15, P(0)=0.20, P(1)=0.25, P(2)=0.15, P(3)=0.1.

  1. Positive (X=1,2,3): 0.25+0.15+0.1=0.50.25+0.15+0.1=0.5.
  2. Non-negative (X=0,1,2,3): 0.2+0.25+0.15+0.1=0.70.2+0.25+0.15+0.1=0.7.
  3. Odd (X=-3,-1,1,3): 0.05+0.15+0.25+0.1=0.550.05+0.15+0.25+0.1=0.55. …

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