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Miscellaneous 7 (II) · Q52
Q.

The probability distribution of discrete r.v. X is as follows

X = x123456
P (X = x)k2k3k4k5k6k
  1. Determine the value of k.
  2. Find P (X ≤ 4) , P (2 < X < 4) , P ( X ≥ 3).
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k+2k+3k+4k+5k+6k=21k=1⇒k=121k+2k+3k+4k+5k+6k=21k=1\Rightarrow k=\dfrac1{21}.

(ii) P(X≤4)=k+2k+3k+4k=10k=1021P(X\le4)=k+2k+3k+4k=10k=\dfrac{10}{21}.

P(2<X<4)=P(X=3)=3k=17P(2<X<4)=P(X=3)=3k=\dfrac17. …

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