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Exercise 3.2 · Q40

Q.In △ABC\triangle ABC, if a=18a = 18, b=24b = 24, c=30c = 30 then find the value of cos⁡A\cos A.

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$\cos A=\dfrac{b^2+c^2-a^2}{2bc}=\dfrac{24^2+30^2-18^2}{2(24)(30)}=\dfrac{576+900-324}{1440}=\dfrac{1152}{ …

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