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Numericals · Q17

Q.A paramagnetic gas has 2.0×10262.0\times10^{26} atoms/m3^3, with an atomic magnetic dipole moment of 1.5×10−231.5\times10^{-23} A m2^2 each. The gas is at 27∘27^\circC.

(a) Find the maximum magnetization intensity of this sample.
(b) If the gas in this problem is kept in a uniform magnetic field of 3 T, is it possible to achieve saturation magnetization? Why? (kB=1.38×10−23k_B=1.38\times10^{-23} J K−1^{-1}) (Hint: find the ratio of the thermal energy of an atom of the gas (32kBT\frac32 k_BT) and the maximum potential energy of the atom (mB), and draw your conclusion.)
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  1. If every atomic dipole were fully aligned, the maximum magnetization would be Mmax=n×m=(2.0×1026)×(1.5×10−23)=3.0×103M_{max}=n\times m=(2.0\times10^{26})\times(1.5\times10^{-23})=3.0\times10^3 A m−1^{-1}.
  2. Saturation requires the applied field's aligning influence (potential energy scale mBmB) to dominate over the randomising effect of thermal agitation (energy scale 32kBT\frac32k_BT). At T=300T=300 K (27∘^\circC): 32kBT=1.5×(1.38×10−23)×300=6.21×10−21\frac32k_BT=1.5\times(1.38\times10^{-23})\times300=6.21\times10^{-21} J. At B=3B=3 T: mB=(1.5×10−23)×3=4.5×10−23mB=(1.5\times10^{-23})\times3=4.5\times10^{-23} J. Since 32kBT≈6.2×10−21\frac32k_BT\approx6.2\times10^{-21} J is roughly 140 times LARGER than mB≈4.5×10−23mB\approx4.5\times10^{-23} J, thermal agitation overwhelmingly dominates over the fie …

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