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Worked Examples · Example 2.12

Q.Doors of a dam are 20 m below the surface of water in the dam. If one door is opened, what will be the speed of the water that flows out of the door? (g = 9.8 m/s²)

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Direct substitution in v=2ghv=\sqrt{2gh}.

From Torricelli's law with h=20h = 20 m: v=2gh=2×9.8×20=392=19.79 m/sv = \sqrt{2gh} = \sqrt{2\times9.8\times20} = \sqrt{392} = 19.79\ \text{m/s} …

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