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Multiple Choice Questions · Q1

Q.A hydraulic lift is designed to lift heavy objects of maximum mass 2000 kg. The area of cross section of piston carrying the load is 2.25×10⁻² m². What is the maximum pressure the piston would have to bear? (A) 0.8711×10⁶ N/m²
(B) 0.5862×10⁷ N/m²
(C) 0.4869×10⁵ N/m²
(D) 0.3271×10⁴ N/m²

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✓ Free question

Step 1. The piston must bear a pressure equal to the maximum load's weight divided by the piston's area: p=mg/Ap = mg/A.

Step 2. Substitute m=2000m = 2000 kg, g=9.8g = 9.8 m/s², A=2.25×10−2A = 2.25×10^{-2} m²: p=(2000×9.8)/(2.25×10−2)=19600/0.0225p = (2000×9.8)/(2.25×10^{-2}) = 19600/0.0225.

Step 3. p=871,111p = 871{,}111 N/m² =0.8711×106= 0.8711×10^6 N/m².

✓Final answer

(A) 0.8711×10⁶ N/m²

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