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Questions 3-23 · Q7

Q.Obtain an expression for conservation of mass starting from the equation of continuity.

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Step 1. Consider a flow tube with two cross-sections of area A1A_1 and A2A_2, where the fluid crosses with speeds v1v_1 and v2v_2 respectively.

Step 2. In a small time interval Δt\Delta t, the mass of fluid entering through A1A_1 is ρA1v1Δt\rho A_1 v_1 \Delta t, and the mass leaving through A2A_2 is ρA2v2Δt\rho A_2 v_2 \Delta t.

Step 3. Since matter can be neither created nor destroyed within the enclosed section of the tube (conservation of mass), these two masses must be equal: ρA1v1Δt=ρA2v2Δt\rho A_1 v_1 \Delta t = \rho A_2 v_2 \Delta t, i.e. ρA1v1=ρA2v2\rho A_1 v_1 = \rho A_2 v_2 — the mass flux is the same at every cross-section. …

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