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Q.A water pipe with a diameter of 5.0 cm is connected to another pipe of diameter 2.5 cm. How would the speeds of the water flow compare — those in the two pipes?

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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v ratio = inverse AREA ratio = (d₁/d₂)² = 4.

The equation of continuity (§2.8) gives A1v1=A2v2A_1v_1 = A_2v_2 for incompressible steady flow. With circular cross-sections A=πd2/4A = \pi d^2/4: v2v1=A1A2=(d1d2)2=(5.02.5)2=4\frac{v_2}{v_1} = \frac{A_1}{A_2} = \left(\frac{d_1}{d_2}\right)^2 = \left(\frac{5.0}{2.5}\right)^2 = 4 The narrow pipe carries the same volume per second through a quarter of the area, so the speed is four times larger. …

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