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Multiple Choice Questions · Q2

Q.Two capillary tubes of radii 0.3 cm and 0.6 cm are dipped in the same liquid. The ratio of heights through which the liquid will rise in the tubes is (A) 1:2
(B) 2:1
(C) 1:4
(D) 4:1

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Step 1. For the same liquid (same T, θ, ρ), capillary rise h=2Tcos⁡θ/(rρg)∝1/rh = 2T\cos\theta/(r\rho g) \propto 1/r.

Step 2. So h1/h2=r2/r1h_1/h_2 = r_2/r_1. With r1=0.3r_1 = 0.3 cm and r2=0.6r_2 = 0.6 cm, h1/h2=0.6/0.3=2h_1/h_2 = 0.6/0.3 = 2.

Step 3. The ratio of heights is h1:h2=2:1h_1 : h_2 = 2 : 1 — the narrower tube (0.3 cm) rises to twice the height of the wider tube (0.6 cm).

✓Final answer

(B) 2:1

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