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Question 84 of 104

Q.Obtain an expression for the rise of a liquid in a capillary tube.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2019Subjective· 3mImportance★★★★★
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Capillary rise results from the balance between the weight of the raised liquid column and the vertical component of the surface tension force around the tube's circumference.

Consider a capillary tube of internal radius rr dipped vertically in a liquid of surface tension TT, density ρ\rho, with angle of contact θ\theta. The liquid rises (for a wetting liquid, θ<90∘\theta<90^{\circ}) to height hh inside the tube.

The upward force supporting the liquid column is provided by the vertical component of the surface tension acting along the circle of contact (circumference 2πr2\pi r) between the liquid and the tube:

Fup=Tcos⁡θ×2πrF_{up} = T\cos\theta \times 2\pi r

This supports the weight of the raised liquid column of height hh (approximating the meniscus volume as negligible or included via correction, in the simple derivation):

W=(πr2h)ρgW = (\pi r^2 h)\rho g

At equilibrium, Fup=WF_{up} = W:

Tcos⁡θ×2πr=πr2hρgT\cos\theta\times2\pi r = \pi r^2 h\rho g

Solving for hh:

h=2Tcos⁡θrρgh = \frac{2T\cos\theta}{r\rho g}

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