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Question 68 of 108

Q.A hole is drilled half way to the centre of the Earth. A body is dropped into the hole. How much will it weigh at the bottom of the hole if the weight of the body on the Earth's surface is 350 N?

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2017Subjective· 2mImportance★★★★★
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Acceleration due to gravity decreases linearly with depth below the Earth's surface: g′=g(1−dR)g' = g\left(1-\dfrac{d}{R}\right).

Inside the Earth (treated as a uniform sphere of radius RR), only the mass enclosed within radius (R−d)(R-d) contributes to the gravitational field at depth dd; the acceleration due to gravity at depth dd is

g′=g(1−dR)g' = g\left(1 - \frac{d}{R}\right)

Here the hole is drilled halfway to the centre, so d=R/2d = R/2:

g′=g(1−R/2R)=g(1−12)=g2g' = g\left(1 - \frac{R/2}{R}\right) = g\left(1-\frac{1}{2}\right) = \frac{g}{2}

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