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Q.A ceiling fan has moment of inertia of 2 kg m². It attains maximum frequency of 60 r.p.m. in 2π seconds. Calculate its power rating.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2026Subjective· 2mImportance★★★★★
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From I=2 kg m2I=2\ \text{kg m}^2 reaching ω=2π rad/s\omega=2\pi\ \text{rad/s} in t=2π st=2\pi\ \text{s}, the average power delivered (work done over time) comes out to 2π≈6.282\pi \approx 6.28 W.

Given: I=2 kg m2I = 2\ \text{kg m}^2, maximum frequency n=60 r.p.m.=1 rev/sn = 60\ \text{r.p.m.} = 1\ \text{rev/s}, time to reach it t=2π st = 2\pi\ \text{s}.

Maximum angular velocity:

ω=2πn=2π(1)=2π rad/s\omega = 2\pi n = 2\pi(1) = 2\pi\ \text{rad/s}

Kinetic energy gained (starting from rest):

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