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Question 59 of 68

Q.Explain the change in internal energy of a thermodynamic system (the gas) by heating it.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2024Subjective· 2mImportance★★★★★
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At constant volume, W=0, so the first law reduces to Q=ΔUQ=\Delta U.

By the first law of thermodynamics, Q=ΔU+WQ = \Delta U + W, where W=∫P dVW = \int P\,dV is the work done by the gas.

If the gas is heated in a rigid, closed container (constant volume), dV=0dV=0 throughout, so W=0W=0. All the heat supplied then goes directly into increasing the internal energy:

Q=ΔUQ = \Delta U …

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