Question 80 of 89
Q.An athlete covers 5 rounds on a circular track of radius 25 m. The total distance and displacement travelled by him is:
(a) 785 m, zero
(b) 942 m, zero
(c) 125 m, zero
(d) zero, zero
Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2025MCQ· 1mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →Distance travelled over 5 complete rounds is 5 times the circumference (250*pi ~ 785 m); displacement is zero because the athlete returns to the exact starting point after each complete round.
Circumference of the track (one round) = 2pir = 2 x pi x 25 m = 50*pi m ~ 157.08 m.
Total distance for 5 rounds (distance is a scalar -- the actual path length travelled, it accumulates regardless of direction):
Distance = 5 x 50pi = 250pi ~ 250 x 3.1416 ~ 785.4 m ~ 785 m
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