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Exercise · Q22

Q.Arrange H3PO2\text{H}_3\text{PO}_2, H3PO3\text{H}_3\text{PO}_3 and H3PO4\text{H}_3\text{PO}_4 in decreasing order of basicity, explaining your answer in terms of the number of P-OH\text{P-OH} groups in each.

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Basicity of a phosphorus oxoacid depends solely on the number of −OH-\text{OH} groups directly bonded to phosphorus, since only these ionise as acidic protons -- any P-H bond present does not ionise. H3PO2\text{H}_3\text{PO}_2 (hypophosphorous acid) has the structure H-P(=O)(OH)H\text{H-P(=O)(OH)H}: just one −OH-\text{OH} group (and two P-H bonds), so it is monobasic. H3PO3\text{H}_3\text{PO}_3 (phosphorous acid) has the structure H-P(=O)(OH)2\text{H-P(=O)(OH)}_2: two −OH-\text{OH} groups (and one P-H bond), so it is dibasic. H3PO4\text{H}_3\text{PO}_4 (orthophosphoric acid) has the structure P(=O)(OH)3\text{P(=O)(OH)}_3: three −OH-\text{OH} groups and no P-H bond at all, so it is fully tribasic. Ordering these by decreasing basicity (most ionisable protons to fewest) gives H3PO4\text{H}_3\text{PO}_4 (tribasic) > H3PO3\text{H}_3\text{PO}_3 (dibas …

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