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Q.At low temperature, phenol reacts with dil. HNO3HNO_3 to yield (A) 2, 4, 6-Trinitrophenol (B) o-Nitrophenol only (C) p-Nitrophenol only (D) ortho-and para-nitrophenol

CBSECBSE Class XII Board 2026MCQ· 1mImportance★★★★★
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Phenol is highly activated toward electrophilic substitution, and dilute nitric acid at low temperature acts as a mild nitrating agent. The reaction yields a mixture of ortho- and para-nitrophenol, with the ortho isomer being the major product due to intramolecular hydrogen bonding.

The key to this question lies in understanding two things: the activating power of the phenolic –OH group, and the conditions under which the nitration is carried out.

Phenol has a hydroxyl group directly attached to the benzene ring. The lone pair on oxygen participates in resonance with the ring, pushing electron density into the ortho and para positions. This makes phenol extremely reactive toward electrophilic substitution — far more than benzene or even toluene. In fact, phenol is so activated that it can be nitrated by very mild reagents like dilute nitric acid, which would barely touch benzene.

Now, the specific conditions here are crucial: dilute HNO₃ at low temperature. This is not the concentrated nitric-sulfuric acid mixture used for benzene. Dilute nitric acid is a much weaker nitrating agent. Under these mild conditions, the reaction stops at mononitration. You do not get further substitution to dinitro or trinitro products because the nitro group, once introduced, is strongly deactivating and makes the ring much less reactive toward a second attack.

Let’s walk through the reasoning step by step.

  1. Identify the directing effect of –OH.

    The hydroxyl group is an ortho-para director. This means the incoming nitro group (NO2+NO_2^+) will attack preferentially at the positions ortho and para to the –OH group. The meta position is not favoured.

  2. Consider the reaction conditions.

    Dilute HNO₃ at low temperature (typically 0–5°C) is a mild nitrating system. It generates a low concentration of the nitronium ion (NO2+NO_2^+). This is important: a low concentration of electrophile means the reaction is selective, and the high reactivity of phenol ensures that mononitration occurs readily.

  3. Predict the product mixture.

    Both ortho and para positions are activated. However, the ortho position is sterically hindered by the bulky –OH group. You might expect the para product to dominate on steric grounds. But here, a special effect comes into play: intramolecular hydrogen bonding.

    In ortho-nitrophenol, the –OH and –NO₂ groups are close enough to form a strong internal hydrogen bond. This stabilises the ortho isomer significantly. The para isomer cannot form such a bond. As a result, ortho-nitrophenol is actually the major product under these conditions, despite the steric hindrance.

  4. Eliminate the other options. …

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