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Q.The magnetic susceptibility of magnesium at 300 K is 1⋅2×10−51\cdot2\times10^{-5}. At what temperature will its magnetic susceptibility become 1⋅44×10−51\cdot44\times10^{-5} ?

(OR)
The magnetic susceptibility χ\chi of a given material is −0⋅5-0\cdot5. Identify the magnetic material.
CBSECBSE Class XII Board 2019Subjective· 1mImportance★★★★★
✓ Free question

Part (a): Curie's law χ∝1/T\chi\propto1/T for paramagnetic magnesium gives T2=χ1T1/χ2=250T_2=\chi_1T_1/\chi_2=250 K. Part (b): χ=−0.5\chi=-0.5 is negative, so the material is diamagnetic.

Magnesium is paramagnetic. For a paramagnet the susceptibility varies inversely with absolute temperature (Curie's law):

χ=CT,\chi=\frac{C}{T},

where CC is the Curie constant. Writing it for the two states,

χ1=CT1,χ2=CT2.\chi_1=\frac{C}{T_1},\qquad \chi_2=\frac{C}{T_2}.

Dividing eliminates CC:

χ1χ2=T2T1 ⇒ T2=T1χ1χ2.\frac{\chi_1}{\chi_2}=\frac{T_2}{T_1}\ \Rightarrow\ T_2=T_1\frac{\chi_1}{\chi_2}.

Substituting T1=300T_1=300 K, χ1=1.2×10−5\chi_1=1.2\times10^{-5}, χ2=1.44×10−5\chi_2=1.44\times10^{-5}:

T2=300×1.2×10−51.44×10−5=300×56=250 K.T_2=300\times\frac{1.2\times10^{-5}}{1.44\times10^{-5}}=300\times\frac{5}{6}=250\ \text{K}.

Tip

χ\chi grew by a factor 1.21.2; since χ∝1/T\chi\propto1/T, the temperature must fall by the same factor: 300/1.2=250300/1.2=250 K.

✓Final answer

T2=250 KT_2=250\ \text{K}.

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