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Q.A signal of low frequency fmf_m is to be transmitted using a carrier wave of frequency fcf_c. Derive the expression for the amplitude modulated wave and deduce expressions for the lower and upper sidebands produced. Hence, obtain the expression for modulation index.

CBSECBSE Class XII Board 2019Subjective· 3mImportance★★★★★
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Amplitude modulation superimposes a low-frequency message signal onto a high-frequency carrier by varying the carrier's amplitude. The modulated wave contains the carrier frequency and two sidebands at fc±fmf_c \pm f_m; the modulation index μ=AmAc\mu = \frac{A_m}{A_c} quantifies the depth of modulation.

Why amplitude modulation works

A low-frequency signal cannot be radiated efficiently by an antenna because the required antenna size is inversely proportional to frequency. We therefore "piggyback" the message signal onto a high-frequency carrier wave by letting the message control the carrier's amplitude. The carrier acts as a vehicle that can travel through space, while the message rides along as variations in its envelope.

Mathematically, we multiply the carrier by a time-varying amplitude factor that depends on the message signal. This multiplication in the time domain creates new frequency components—the sidebands—that carry the information.

Derivation of the amplitude modulated wave

  1. Define the message and carrier signals

    The message (modulating) signal is sinusoidal:

m(t)=Amsin⁡(2πfmt)m(t) = A_m \sin(2\pi f_m t)

where AmA_m is the message amplitude and fmf_m is the message frequency.

The carrier wave is:

c(t)=Acsin⁡(2πfct)c(t) = A_c \sin(2\pi f_c t)

where AcA_c is the carrier amplitude and fc≫fmf_c \gg f_m is the carrier frequency.

  1. Construct the modulated amplitude

    In amplitude modulation, the instantaneous amplitude of the carrier varies linearly with the message signal. We write:

A(t)=Ac+m(t)=Ac+Amsin⁡(2πfmt)A(t) = A_c + m(t) = A_c + A_m \sin(2\pi f_m t)

This can be rewritten as:

A(t)=Ac[1+AmAcsin⁡(2πfmt)]A(t) = A_c \left[1 + \frac{A_m}{A_c} \sin(2\pi f_m t)\right]

  1. Form the AM wave

    The amplitude-modulated signal is the carrier with time-varying amplitude:

s(t)=A(t)⋅sin⁡(2πfct)s(t) = A(t) \cdot \sin(2\pi f_c t)

s(t)=Ac[1+AmAcsin⁡(2πfmt)]sin⁡(2πfct)s(t) = A_c \left[1 + \frac{A_m}{A_c} \sin(2\pi f_m t)\right] \sin(2\pi f_c t)

Define the modulation index μ=AmAc\mu = \frac{A_m}{A_c}, which measures the fractional change in amplitude:

s(t)=Ac[1+μsin⁡(2πfmt)]sin⁡(2πfct)s(t) = A_c [1 + \mu \sin(2\pi f_m t)] \sin(2\pi f_c t)

  1. Expand to reveal the frequency components

    Distribute the carrier:

s(t)=Acsin⁡(2πfct)+μAcsin⁡(2πfmt)sin⁡(2πfct)s(t) = A_c \sin(2\pi f_c t) + \mu A_c \sin(2\pi f_m t) \sin(2\pi f_c t)

Apply the product-to-sum trigonometric identity:

sin⁡Asin⁡B=12[cos⁡(A−B)−cos⁡(A+B)]\sin A \sin B = \frac{1}{2}[\cos(A - B) - \cos(A + B)]

With A=2πfmtA = 2\pi f_m t and B=2πfctB = 2\pi f_c t:

sin⁡(2πfmt)sin⁡(2πfct)=12[cos⁡2π(fc−fm)t−cos⁡2π(fc+fm)t]\sin(2\pi f_m t) \sin(2\pi f_c t) = \frac{1}{2}[\cos 2\pi(f_c - f_m)t - \cos 2\pi(f_c + f_m)t]

  1. Write the complete AM expression

    Substituting back:

s(t)=Acsin⁡(2πfct)+μAc2cos⁡2π(fc−fm)t−μAc2cos⁡2π(fc+fm)ts(t) = A_c \sin(2\pi f_c t) + \frac{\mu A_c}{2} \cos 2\pi(f_c - f_m)t - \frac{\mu A_c}{2} \cos 2\pi(f_c + f_m)t

Important

The AM wave consists of three frequency components:

  • Carrier: frequency fcf_c, amplitude AcA_c
  • Lower sideband (LSB): frequency fc−fmf_c - f_m, amplitude μAc2\frac{\mu A_c}{2}
  • Upper sideband (USB): frequency fc+fmf_c + f_m, amplitude μAc2\frac{\mu A_c}{2}

Sideband expressions …

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