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Q.(a) Differentiate between nuclear fission and nuclear fusion.

(b) Deuterium undergoes fusion as per the reaction : 12H+12H→23He+01n+3⋅27 MeV{}_{1}^{2}\mathrm{H} + {}_{1}^{2}\mathrm{H} \rightarrow {}_{2}^{3}\mathrm{He} + {}_{0}^{1}\mathrm{n} + 3\cdot27\ \mathrm{MeV} Find the duration for which an electric bulb of 500 W can be kept glowing by the fusion of 100 g of deuterium.
CBSECBSE Class XII Board 2022Subjective· 3mImportance★★★★★
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(a) Fission splits a heavy nucleus into lighter ones; fusion joins light nuclei into a heavier one. (b) The fusion of 100 g100\ \text{g} of deuterium releases about 7.9×1012 J7.9\times10^{12}\ \text{J}, enough to keep a 500 W500\ \text{W} bulb glowing for about 1.6×1010 s≈5001.6\times10^{10}\ \text{s}\approx 500 years.

(a) Fission vs fusion

FeatureNuclear fissionNuclear fusion
ProcessA heavy nucleus splits into two lighter nucleiTwo light nuclei combine into a heavier nucleus
Typical fuelHeavy nuclei (U-235, Pu-239)Light nuclei (isotopes of hydrogen)
Energy per reaction∼200 MeV\sim 200\ \text{MeV}A few MeV (but far more per unit mass)
ConditionsProceeds with slow neutrons at ordinary temperatureNeeds extremely high temperature and pressure
ProductsRadioactive fission fragmentsLight, generally non-radioactive nuclei (e.g. He)

(b) Time a 500 W bulb glows on 100 g of deuterium

The reaction consumes two deuterons and releases 3.27 MeV3.27\ \text{MeV}:

12H+12H→23He+01n+3.27 MeV.{}_{1}^{2}\mathrm{H}+{}_{1}^{2}\mathrm{H}\rightarrow{}_{2}^{3}\mathrm{He}+{}_{0}^{1}\mathrm{n}+3.27\ \text{MeV}.

Number of deuterons in 100 g100\ \text{g} (molar mass ≈2 g/mol\approx 2\ \text{g/mol}):

N=1002×NA=50×6.022×1023=3.01×1025.N=\frac{100}{2}\times N_A=50\times 6.022\times10^{23}=3.01\times10^{25}.

Number of reactions (two deuterons each):

nrxn=N2=1.51×1025.n_{\text{rxn}}=\frac{N}{2}=1.51\times10^{25}. …

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