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Solved Examples · Example 9

Q.Multiply 35H by 45H

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[!TLDR]

Load 35H into A and 45H into B, run MUL AB, and the 16-bit product 0E49H appears as A = 49H (low) and B = 0EH (high).

Concept - MUL AB. Byte-by-byte unsigned multiplication uses MUL AB (no comma between A and B). One operand must be in A and the other in B; after execution the 16-bit product is split with its low byte in A and its high byte in B.

Program:

MOV A, #35H   ; load 35H into A
MOV B, #45H   ; load 45H into B
MUL AB        ; A x B, product in B:A
``` …

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