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Electronics · Ch 8 — Modulation and Demodulation

Analysis of Amplitude Modulated Wave

8.3

Analysis of Amplitude Modulated Wave

To describe an AM wave mathematically, let the modulating signal be

vm=Vmsin⁡(ωmt)(8.1),ωm=2πfmv_m = V_m \sin(\omega_m t) \qquad (8.1), \quad \omega_m = 2\pi f_m

and the carrier be

vC=VCsin⁡(ωct)(8.2),ωc=2πfcv_C = V_C \sin(\omega_c t) \qquad (8.2), \quad \omega_c = 2\pi f_c

where the carrier phase is ignored for simplicity and fc≫fmf_c \gg f_m. During amplitude modulation the carrier amplitude is no longer constant but becomes

A=VC+vm(8.3)=VC(1+VmVCsin⁡ωmt)=VC(1+masin⁡ωmt)A = V_C + v_m \qquad (8.3) = V_C\left(1 + \tfrac{V_m}{V_C}\sin\omega_m t\right) = V_C(1 + m_a \sin\omega_m t)

The instantaneous AM signal is therefore

vAM=Asin⁡(ωct)(8.4)=VC(1+masin⁡ωmt)sin⁡(ωct)(8.5)v_{AM} = A \sin(\omega_c t) \qquad (8.4) = V_C(1 + m_a \sin\omega_m t)\sin(\omega_c t) \qquad (8.5)

Here ma=Vm/VCm_a = V_m/V_C is called the modulation index (also modulation factor or depth of modulation). Expanding equation (8.5) using a product-to-sum identity gives the AM wave as the sum of three components:

vAM=VCsin⁡(ωct)+maVC2cos⁡ ⁣((ωc−ωm)t)−maVC2cos⁡ ⁣((ωc+ωm)t)(8.6)v_{AM} = V_C \sin(\omega_c t) + \tfrac{m_a V_C}{2}\cos\!\big((\omega_c-\omega_m)t\big) - \tfrac{m_a V_C}{2}\cos\!\big((\omega_c+\omega_m)t\big) \qquad (8.6)

These three terms are the carrier (amplitude VCV_C, frequency fcf_c), the lower sideband (amplitude maVC/2m_a V_C/2, frequency fc−fmf_c - f_m) and the upper sideband (amplitude maVC/2m_a V_C/2, frequency fc+fmf_c + f_m). Notably, the modulated wave contains no component at the original modulating frequency fmf_m.

Frequency spectrum of AM wave

A frequency spectrum is a graph of the amplitude of a wave versus frequency. For an AM wave (Figure 8.2.2) it consists of three vertical lines: the carrier at fcf_c (height VCV_C), the lower side frequency at fc−fmf_c - f_m and the upper side frequency at fc+fmf_c + f_m, each of height maVC/2m_a V_C/2, spaced equally on either side of the carrier. The two side frequencies are the sidebands — the sum and difference signals produced by modulation. The carrier itself carries no information; the message resides entirely in the sidebands.

Bandwidth

The bandwidth of the AM wave is the frequency range from the lower to the upper sideband:

BW=fUSB−fLSB=(fc+fm)−(fc−fm)=2fm(8.7)BW = f_{USB} - f_{LSB} = (f_c + f_m) - (f_c - f_m) = 2 f_m \qquad (8.7)

So an AM channel needs a bandwidth of twice the highest modulating frequency. In practice a medium-wave AM broadcast station is allocated a 9 kHz-wide channel.

Modulation index

For proper amplitude modulation VmV_m must be less than VCV_C, so that

ma=VmVC(8.8)m_a = \frac{V_m}{V_C} \qquad (8.8)

lies between 0 and 1, with a maximum permitted value of 1.0. If VmV_m exceeds VCV_C then ma>1m_a > 1, which causes over-modulation and a distorted envelope. The modulation is often stated as a percentage:

M=VmVC×100(8.9)M = \frac{V_m}{V_C} \times 100 \qquad (8.9)

Modulation index from V_max and V_min

The modulation index can be found directly from an AM waveform displayed on an oscilloscope (Figure 8.2.3). The maximum and minimum envelope amplitudes are

Vmax=VC+maVC(8.10),Vmin=VC−maVC(8.11)V_{max} = V_C + m_a V_C \qquad (8.10), \qquad V_{min} = V_C - m_a V_C \qquad (8.11)

Adding and subtracting these gives

VC=Vmax+Vmin2(8.12),maVC=Vmax−Vmin2(8.13)V_C = \frac{V_{max}+V_{min}}{2} \quad (8.12), \qquad m_a V_C = \frac{V_{max}-V_{min}}{2} \quad (8.13)

so that the standard working formula is

ma=Vmax−VminVmax+Vmin(8.14)m_a = \frac{V_{max}-V_{min}}{V_{max}+V_{min}} \qquad (8.14)

When the AM wave is observed as an antenna current instead of a voltage, the same relation holds with currents:

ma=Imax−IminImax+Imin(8.15)m_a = \frac{I_{max}-I_{min}}{I_{max}+I_{min}} \qquad (8.15)

Modulated waves with various degrees of modulation

The shape of the AM wave depends on the value of ma=Vm/VCm_a = V_m/V_C:

  • ma=0m_a = 0 (Figure 8.2.4): no modulating signal; the output is just the unmodulated carrier of constant peak amplitude AA. …
Formula 1Modulating signal and carrier signal

vm=Vmsin⁡(ωmt)v_m = V_m \sin(\omega_m t) (8.1) and vC=VCsin⁡(ωct)v_C = V_C \sin(\omega_c t) (8.2), with ωm=2πfm\omega_m = 2\pi f_m, ωc=2πfc\omega_c = 2\pi f_c and fc≫fmf_c \gg f_m. Here VmV_m and VCV_C are the peak amplitudes and fm,fcf_m, f_c the frequencies of the message and carrier (with the carrier phase ignored); these two expressions …

Formula 2Standard AM wave equation

vAM=VC(1+masin⁡ωmt)sin⁡(ωct)v_{AM} = V_C(1 + m_a \sin\omega_m t)\sin(\omega_c t) (8.5), obtained from vAM=Asin⁡ωctv_{AM} = A\sin\omega_c t with the modulated amplitude A=VC(1+masin⁡ωmt)A = V_C(1 + m_a \sin\omega_m t). Here ma=Vm/VCm_a = V_m/V_C is the modulation index; expanding this product with a product-to-sum identity gives the AM w …

Definition 3Modulation index (modulation factor / depth of modulation)

ma=Vm/VCm_a = V_m/V_C: the ratio of modulating-signal amplitude to carrier amplitude. It must lie between 0 and 1 (maximum 1.0); a value greater than 1 causes over-modulation and envelope distortion. Because it fixes both the quality and the strength of the transmitted signal, the modulation …

Formula 4AM wave as carrier plus two sidebands

vAM=VCsin⁡ωct+maVC2cos⁡(ωc−ωm)t−maVC2cos⁡(ωc+ωm)tv_{AM} = V_C\sin\omega_c t + \tfrac{m_a V_C}{2}\cos(\omega_c-\omega_m)t - \tfrac{m_a V_C}{2}\cos(\omega_c+\omega_m)t (8.6): the carrier at fcf_c, the lower sideband at fc−fmf_c - f_m and the upper sideband at fc+fmf_c + f_m, the …

Definition 5Sidebands (upper and lower side frequencies)

The sum frequency fc+fmf_c + f_m (upper sideband) and difference frequency fc−fmf_c - f_m (lower sideband) produced by modulation. Each has amplitude maVC/2m_a V_C/2; the carrier carries no information, so all t …

Formula 6Bandwidth of an AM wave

BW=fUSB−fLSB=(fc+fm)−(fc−fm)=2fmBW = f_{USB} - f_{LSB} = (f_c+f_m)-(f_c-f_m) = 2 f_m (8.7): twice the highest modulating frequency. Here fUSB=fc+fmf_{USB} = f_c + f_m is the upper side frequency and fLSB=fc−fmf_{LSB} = f_c - f_m the lower one, so an AM channel needs a bandwidth of twice the highest modulating frequency; a medium-wave A …

Formula 7Percentage of modulation

M=VmVC×100M = \dfrac{V_m}{V_C}\times 100 (8.9), the modulation index expressed as a percentage. Here VmV_m is the modulating-signal amplitude and VCV_C the carrier amplitude, so the percentage is simply the modulation index scaled by 100. For undistorted AM it stays at or below 100%; a higher v …

Formula 8Modulation index from V_max and V_min

ma=Vmax−VminVmax+Vminm_a = \dfrac{V_{max}-V_{min}}{V_{max}+V_{min}} (8.14), with VC=(Vmax+Vmin)/2V_C = (V_{max}+V_{min})/2. This is the standard method of measuring mam_a from an oscilloscope trace. Here VmaxV_{max} and VminV_{min} are the peak and trough amplitudes of the AM envelope, read directly from an oscilloscope trace, so no separate k …

Formula 9Modulation index in terms of current

ma=Imax−IminImax+Iminm_a = \dfrac{I_{max}-I_{min}}{I_{max}+I_{min}} (8.15), used when the AM wave is measured as an antenna current. Here ImaxI_{max} and IminI_{min} are the maximum and minimum envelope currents; this mirrors the voltage form ma=(Vmax−Vmin)/(Vmax+Vmin)m_a = (V_{max}-V_{min})/(V_{max}+V_{min}) and is used when the AM wave is …

Figure 10Frequency spectrum of an AM wave showing carrier with lower and upper sidebands and a 2f_m bandwidth
Fig. 10 — Frequency spectrum of an AM wave showing carrier with lower and upper sidebands and a 2f_m bandwidth

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

Figure 8.2.2 (Frequency spectrum of AM wave): amplitude-versus-frequency graph with the carrier line at fcf_c (height VCV_C) flanked by the lower sideband at fc−fmf_c - f_m and upper sideband at fc+fmf_c + f_m, each of height maVC/2m_a V_C/2; …

Figure 11Oscilloscope AM waveform used to derive the modulation index from V_max and V_min
Fig. 11 — Oscilloscope AM waveform used to derive the modulation index from V_max and V_min

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

Figure 8.2.3 (Amplitude modulated wave): a modulated carrier whose upper envelope traces (VC+Vmsin⁡ωmt)(V_C + V_m\sin\omega_m t) and lower envelope its mirror image; the right side brackets the peak envelope VmaxV_{max} and trough VminV_{min}, and the left marks the unmodulated carrier level VCV_C. Used to …

Figure 12AM wave for modulation index zero, identical to the unmodulated carrier of amplitude A
Fig. 12 — AM wave for modulation index zero, identical to the unmodulated carrier of amplitude A

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

Figure 8.2.4 (Amplitude modulation for ma=0m_a = 0): with no modulating signal the AM wave equals the unmodulated carrier of constant amplitude AA. What to notice: the peak amplitude stays constant and the envelope is a flat, unchanging line — with no message applied there is nothing to trace, so the output is in …

Figure 13AM wave at fifty percent modulation whose envelope never reaches the zero axis
Fig. 13 — AM wave at fifty percent modulation whose envelope never reaches the zero axis

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

Figure 8.2.5 (Amplitude modulation for ma=0.5m_a = 0.5): carrier of amplitude AA plus a 0.5A signal gives an AM wave peaking at 1.5A whose envelope keeps a distinct waist and does not touch zer …

Figure 14AM wave at one hundred percent modulation whose envelope just touches the zero axis
Fig. 14 — AM wave at one hundred percent modulation whose envelope just touches the zero axis

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

Figure 8.2.6 (Amplitude modulation for ma=1m_a = 1): carrier plus an equal-amplitude signal gives an AM wave peaking at 2A whose envelope pinches down to touch the zero axi …

Figure 15Over-modulated AM wave at index one point five with clipped negative peaks showing splattering
Fig. 15 — Over-modulated AM wave at index one point five with clipped negative peaks showing splattering

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

Figure 8.2.7 (Amplitude modulation for ma=1.5m_a = 1.5): a 1.5A signal over-modulates the carrier; the envelope peaks at 2.5A and is flattened near zero with the negative peaks clipped, producing …