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Q.An amplitude modulated wave has a carrier amplitude of 50 V and signal amplitude of 20 V. What is the modulation index and percentage of modulation?

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[!TLDR]

With Vm=20V_m = 20 V and VC=50V_C = 50 V, the modulation index is ma=0.4m_a = 0.4 and the percentage of modulation is 40%.

In amplitude modulation the extent to which the carrier amplitude is varied by the modulating signal is measured by the modulation index (also called the modulation factor or depth of modulation). It is defined as the ratio of the peak amplitude of the modulating signal to the peak amplitude of the carrier:

ma=VmVCm_a = \frac{V_m}{V_C}

A well-behaved AM wave has mam_a between 0 and 1; a value of 1 corresponds to 100% modulation and anything above it causes over-modulation and envelope distortion. The percentage of modulation expresses the same quantity on a 0-100 scale, M=(Vm/VC)×100M = (V_m/V_C)\times 100.

Given Vm=20V_m = 20 V and VC=50V_C = 50 V:

ma=VmVC=2050=0.4m_a = \frac{V_m}{V_C} = \frac{20}{50} = 0.4

M=0.4×100=40%M = 0.4 \times 100 = 40\%

Since ma<1m_a < 1, the wave is properly modulated and its envelope can be recovered without distortion.

[!ANSWER]

ma=0.4m_a = 0.4, percentage of modulation M=40%M = 40\%

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