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Exercises · Q4

Q.Which of the following relations from A={1,2,3}A=\{1,2,3\} to B={p,q}B=\{p,q\} is a function?

(a) {(1,p),(1,q),(2,p),(3,q)}\{(1,p),(1,q),(2,p),(3,q)\}
(b) {(1,p),(2,q)}\{(1,p),(2,q)\}
(c) {(1,q),(2,q),(3,q)}\{(1,q),(2,q),(3,q)\}
(d) {(1,p),(2,q),(3,p),(3,q)}\{(1,p),(2,q),(3,p),(3,q)\}
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✓ Free question

For a relation from A={1,2,3}A=\{1,2,3\} to B={p,q}B=\{p,q\} to be a function, every element of AA must be the first component of exactly one ordered pair.

(a) {(1,p),(1,q),(2,p),(3,q)}\{(1,p),(1,q),(2,p),(3,q)\}: the element 11 appears twice (with pp and with qq) — two images, violating uniqueness. Not a function.

(b) {(1,p),(2,q)}\{(1,p),(2,q)\}: the element 3∈A3\in A has no image at all — violating existence. Not a function.

(c) {(1,q),(2,q),(3,q)}\{(1,q),(2,q),(3,q)\}: each of 1,2,31,2,3 appears exactly once, all mapped to qq. Every element of AA has exactly one image, so this is a function (a constant function; it happens to be many-one and into, but it is still a function).

(d) {(1,p),(2,q),(3,p),(3,q)}\{(1,p),(2,q),(3,p),(3,q)\}: the element 33 appears twice — two images. Not a function.

Only (c) satisfies the definition.

✓Final answer

Option (c), {(1,q),(2,q),(3,q)}\{(1,q),(2,q),(3,q)\}, is the only relation that is a function, since it is the only one where every element of AA has exactly one image, with none omitted or repeated.

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