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Exercises · Q8

Q.Given f(x)=x2−1f(x)=x^2-1 and g(x)=x+2g(x)=x+2, find (f∘g)(x)(f\circ g)(x) and (g∘f)(x)(g\circ f)(x), and show they are not equal.

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(f∘g)(x)=f(g(x))(f\circ g)(x)=f(g(x)) — apply gg first:

g(x)=x+2,g(x)=x+2,

f(x+2)=(x+2)2−1=(x2+4x+4)−1=x2+4x+3.f(x+2)=(x+2)^2-1=(x^2+4x+4)-1=x^2+4x+3.

So (f∘g)(x)=x2+4x+3(f\circ g)(x)=x^2+4x+3.

(g∘f)(x)=g(f(x))(g\circ f)(x)=g(f(x)) — apply ff first:

f(x)=x2−1,f(x)=x^2-1,

g(x2−1)=(x2−1)+2=x2+1.g(x^2-1)=(x^2-1)+2=x^2+1.

So (g∘f)(x)=x2+1(g\circ f)(x)=x^2+1. …

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