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Exercises · Q7

Q.Determine whether each function is even, odd, or neither:

(i) f(x)=x4−3x2f(x)=x^4-3x^2
(ii) g(x)=x3+2xg(x)=x^3+2x
(iii) h(x)=x2+xh(x)=x^2+x.
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(i) f(x)=x4−3x2f(x)=x^4-3x^2. Compute f(−x)f(-x):

f(−x)=(−x)4−3(−x)2=x4−3x2=f(x).f(-x)=(-x)^4-3(-x)^2=x^4-3x^2=f(x).

Since f(−x)=f(x)f(-x)=f(x) for all xx, ff is even.

(ii) g(x)=x3+2xg(x)=x^3+2x. Compute g(−x)g(-x):

g(−x)=(−x)3+2(−x)=−x3−2x=−(x3+2x)=−g(x).g(-x)=(-x)^3+2(-x)=-x^3-2x=-(x^3+2x)=-g(x).

Since g(−x)=−g(x)g(-x)=-g(x) for all xx, gg is odd (and consistently g(0)=0g(0)=0).

(iii) h(x)=x2+xh(x)=x^2+x. Compute h(−x)h(-x):

h(−x)=(−x)2+(−x)=x2−x.h(-x)=(-x)^2+(-x)=x^2-x.

Compare: h(x)=x2+xh(x)=x^2+x and −h(x)=−x2−x-h(x)=-x^2-x. Since x2−xx^2-x equals neither of these (they differ in the sign of one term), hh is neither even nor odd. …

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