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MISCELLANEOUS EXERCISE-8 · Q59

Q.Discuss the continuity of the following function at the point(s) or on the interval indicated against it: f(x)=⌊x+1⌋f(x) = \lfloor x+1 \rfloor for x∈[−2,2)x \in [-2,2), where ⌊ ⌋\lfloor \, \rfloor is the greatest integer function.

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f(x)=⌊x+1⌋f(x)=\lfloor x+1\rfloor for x∈[−2,2)x\in[-2,2). As xx ranges over [−2,2)[-2,2), x+1x+1 ranges over [−1,3)[-1,3), and ⌊x+1⌋\lfloor x+1\rfloor jumps wherever x+1x+1 is an integer, i.e. at x=−1,0,1,2x=-1,0,1,2; but x=2x=2 is excluded from the domain, so the relevant jump points inside [−2,2)[-2,2) are x=−1,0,1x=-1,0,1.

At each such point n∈{−1,0,1}n\in\{-1,0,1\}: f(n)=⌊n+1⌋=n+1f(n)=\lfloor n+1\rfloor=n+1 (right-continuous value), while lim⁡x→n−f(x)=n\displaystyle\lim_{x\to n^-} f(x)=n (the value just below). Since n≠n+1n\ne n+1, both one-sided limits exist (as nn and n+1n+1) but differ — a jump discontinuity of size 11 at each of x=−1,0,1x=-1,0,1. …

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