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MISCELLANEOUS EXERCISE-8 · Q63

Q.Identify discontinuities if any for the following function as either a jump or a removable discontinuity on its domain: f(x)=x2+x+1x+1f(x) = \dfrac{x^2+x+1}{x+1}, for x∈[0,3)x \in [0,3), =3x+4x2−5= \dfrac{3x+4}{x^2-5}, for x∈[3,6]x \in [3,6].

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f(x)=x2+x+1x+1f(x)=\dfrac{x^2+x+1}{x+1} for x∈[0,3)x\in[0,3), and f(x)=3x+4x2−5f(x)=\dfrac{3x+4}{x^2-5} for x∈[3,6]x\in[3,6]. The only point to check is the junction x=3x=3 (each piece is individually continuous on its own sub-domain: the first has no zero of x+1x+1 in [0,3)[0,3), and the second has no zero of x2−5x^2-5 in [3,6][3,6], since 5≈2.24<3\sqrt5\approx2.24<3).

Left-hand limit: lim⁡x→3−x2+x+1x+1=9+3+14=134\displaystyle\lim_{x\to3^-}\frac{x^2+x+1}{x+1}=\frac{9+3+1}{4}=\frac{13}{4}. …

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