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MISCELLANEOUS EXERCISE-8 · Q67

Q.Find kk if the following function is continuous at the point indicated against it: f(x)=45x−9x−5x+1(kx−1)(3x−1)f(x) = \dfrac{45^x-9^x-5^x+1}{(k^x-1)(3^x-1)}, for x≠0x \ne 0, =23= \dfrac23, for x=0x=0, at x=0x=0.

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f(x)=45x−9x−5x+1(kx−1)(3x−1)f(x)=\dfrac{45^x-9^x-5^x+1}{(k^x-1)(3^x-1)} for x≠0x\ne0, f(0)=23f(0)=\dfrac23.

Numerator: since 45x=9x⋅5x45^x=9^x\cdot5^x, 45x−9x−5x+1=9x(5x−1)−(5x−1)=(5x−1)(9x−1)45^x-9^x-5^x+1=9^x(5^x-1)-(5^x-1)=(5^x-1)(9^x-1). …

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